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Friday, November 8, 2013

Physics Spring Constant

TITLE: Finding the bounce constant utilize the prise of force/ aggregate to multiplication applied on a forswear. ABSTRACT: The spring constant/force constant/ unwieldiness of a spring can be reason exploitation the gradient of force and extension graph.(Hookes law; Fe) supposition: From Hookes law, which states provided the elastic limit of an elastic material is not exceeded, the extension (e) of the material is directly proportional to the load or applied force. Fe F=ke Using the equation of a straightaway line graph, Comparing the equations; Y=mx + c E=F/k There forwards; m=1/k K=1/m gimmick: * Spiral spring * Retort stand * 100g mass hunger * 15 100g masses * rule * graph paper * cursor * shopping centre goggle METHOD/PROCEDURE: * The voluted spring was hung on the takings stand. * The length of the spiral spring was measured before all mass was hung.
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* 100g mass was hung and the extension was measured and record * This was repeated until a mass of 1500g was reached and recorded * The graph of extension against force was plotted * The gradient was calculated * The fore constant was then calculated from the gradient pass: g=10metres per fleck squared Original length of spring=5cm Force=mass x acceleration Mass/g| Force/N| quotation/m (1)| Extension/m (2)| Extension /m (3)| extension(1+2+3)/3| 100| 1| 0.038| 0.035| 0.041| 0.038| 200| 2| 0.072| 0.077| 0.079| 0.076| three hundred| 3| 0.116| 0.116| 0.113| 0.115| cd| 4| 0.153| 0.154| 0.154| 0.154| 500| 5| 0.191| 0.192| 0.193| 0.192| 600| 6| 0.2 27| 0.233| 0.233| 0.231| 700| 7| 0.268| 0.! 269| 0.267| 0.269| 800| 8| 0.307| 0.309| 0.308| 0.308| 900| 9| 0.346| 0.345| 0.347| 0.346| 1000| 10| 0.381| 0.387| 0.387| 0.385| 1100| 11| 0.422| 0.424| 0.423| 0.423| 1200| 12| 0.460| 0.463| 0.463| 0.462| 1300| 13| 0.500| 0.500| 0.500| 0.500| 1400| 14| 0.510|...If you want to get a full essay, run it on our website: OrderEssay.net

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